(3x+5)^2-(2x-7)^2=24(2x-1)

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Solution for (3x+5)^2-(2x-7)^2=24(2x-1) equation: 



(3x+5)^2-(2x-7)^2=24(2x-1)

We move all terms to the left:

(3x+5)^2-(2x-7)^2-(24(2x-1))=0



We calculate terms in parentheses: -(24(2x-1)), so:

24(2x-1)

We multiply parentheses

48x-24

Back to the equation:

-(48x-24)



We get rid of parentheses

(3x+5)^2-(2x-7)^2-48x+24=0

We add all the numbers together, and all the variables

-48x+(3x+5)^2-(2x-7)^2+24=0

We move all terms containing x to the left, all other terms to the right

-48x+(3x+5)^2-(2x-7)^2=-24

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